第1章程序設(shè)計(jì)和C語(yǔ)言11.1什么是計(jì)算機(jī)程序11.2什么是計(jì)算機(jī)語(yǔ)言11.3C語(yǔ)言的發(fā)展及其特點(diǎn)31.4最簡(jiǎn)單的C語(yǔ)言程序51.4.1最簡(jiǎn)單的C語(yǔ)言程序舉例61.4.2C語(yǔ)言程序的結(jié)構(gòu)101.5運(yùn)行C程序的步驟與方法121.6程序設(shè)計(jì)的任務(wù)141-5 #include <stdio.h>int main ( ) printf ("*nn");printf(" Very Good!nn");printf ("*n");return 0;1-6#include <stdio.h>int main()int a,b,c,max;printf("please input a,b,c:n");scanf("%d,%d,%d",&a,&b,&c);max=a;if (max<b)max=b;if (max<c)max=c;printf("The largest number is %dn",max);return 0;第2章算法程序的靈魂162.1什么是算法162.2簡(jiǎn)單的算法舉例172.3算法的特性212.4怎樣表示一個(gè)算法222.4.1用自然語(yǔ)言表示算法222.4.2用流程圖表示算法222.4.3三種基本結(jié)構(gòu)和改進(jìn)的流程圖262.4.4用NS流程圖表示算法282.4.5用偽代碼表示算法312.4.6用計(jì)算機(jī)語(yǔ)言表示算法322.5結(jié)構(gòu)化程序設(shè)計(jì)方法34習(xí)題36第章最簡(jiǎn)單的C程序設(shè)計(jì)順序程序設(shè)計(jì)373.1順序程序設(shè)計(jì)舉例373.2數(shù)據(jù)的表現(xiàn)形式及其運(yùn)算393.2.1常量和變量393.2.2數(shù)據(jù)類(lèi)型423.2.3整型數(shù)據(jù)443.2.4字符型數(shù)據(jù)473.2.5浮點(diǎn)型數(shù)據(jù)493.2.6怎樣確定常量的類(lèi)型513.2.7運(yùn)算符和表達(dá)式523.3C語(yǔ)句573.3.1C語(yǔ)句的作用和分類(lèi)573.3.2最基本的語(yǔ)句賦值語(yǔ)句593.4數(shù)據(jù)的輸入輸出653.4.1輸入輸出舉例653.4.2有關(guān)數(shù)據(jù)輸入輸出的概念673.4.3用printf函數(shù)輸出數(shù)據(jù)683.4.4用scanf函數(shù)輸入數(shù)據(jù)753.4.5字符數(shù)據(jù)的輸入輸出78習(xí)題823-1 #include <stdio.h>#include <math.h>int main()float p,r,n;r=0.1;n=10;p=pow(1+r,n);printf("p=%fn",p);return 0;3-2-1#include <stdio.h>#include <math.h>int main()float r5,r3,r2,r1,r0,p,p1,p2,p3,p4,p5;p=1000;r5=0.0585;r3=0.054;r2=0.0468;r1=0.0414;r0=0.0072;p1=p*(1+r5)*5); / 一次存5年期p2=p*(1+2*r2)*(1+3*r3); / 先存2年期，到期后將本息再存3年期p3=p*(1+3*r3)*(1+2*r2); / 先存3年期，到期后將本息再存2年期p4=p*pow(1+r1,5); / 存1年期，到期后將本息存再存1年期，連續(xù)存5次 p5=p*pow(1+r0/4,4*5); / 存活期存款?；钇诶⒚恳患径冉Y(jié)算一次printf("p1=%fn",p1); / 輸出按第1方案得到的本息和printf("p2=%fn",p2); / 輸出按第2方案得到的本息和printf("p3=%fn",p3); / 輸出按第3方案得到的本息和printf("p4=%fn",p4); / 輸出按第4方案得到的本息和printf("p5=%fn",p5); / 輸出按第5方案得到的本息和return 0;3-2-2#include <stdio.h>#include <math.h>int main()double r5,r3,r2,r1,r0,p,p1,p2,p3,p4,p5;p=1000;r5=0.0585;r3=0.054;r2=0.0468;r1=0.0414;r0=0.0072;p1=p*(1+r5)*5); / 一次存5年期p2=p*(1+2*r2)*(1+3*r3); / 先存2年期，到期后將本息再存3年期p3=p*(1+3*r3)*(1+2*r2); / 先存3年期，到期后將本息再存2年期p4=p*pow(1+r1,5); / 存1年期，到期后將本息存再存1年期，連續(xù)存5次 p5=p*pow(1+r0/4,4*5); / 存活期存款?；钇诶⒚恳患径冉Y(jié)算一次printf("p1=%fn",p1); / 輸出按第1方案得到的本息和printf("p2=%fn",p2); / 輸出按第2方案得到的本息和printf("p3=%fn",p3); / 輸出按第3方案得到的本息和printf("p4=%fn",p4); / 輸出按第4方案得到的本息和printf("p5=%fn",p5); / 輸出按第5方案得到的本息和return 0;3-2-3#include <stdio.h>#include <math.h>int main()float r5,r3,r2,r1,r0,p,p1,p2,p3,p4,p5;p=1000;r5=0.0585;r3=0.054;r2=0.0468;r1=0.0414;r0=0.0072;p1=p*(1+r5)*5); / 一次存5年期p2=p*(1+2*r2)*(1+3*r3); / 先存2年期，到期后將本息再存3年期p3=p*(1+3*r3)*(1+2*r2); / 先存3年期，到期后將本息再存2年期p4=p*pow(1+r1,5); / 存1年期，到期后將本息存再存1年期，連續(xù)存5次 p5=p*pow(1+r0/4,4*5); / 存活期存款。活期利息每一季度結(jié)算一次printf("p1=%10.2fn",p1); / 輸出按第1方案得到的本息和printf("p2=%10.2fn",p2); / 輸出按第2方案得到的本息和printf("p3=%10.2fn",p3); / 輸出按第3方案得到的本息和printf("p4=%10.2fn",p4); / 輸出按第4方案得到的本息和printf("p5=%10.2fn",p5); / 輸出按第5方案得到的本息和return 0;3-3.#include <stdio.h>#include <math.h>int main()float d=300000,p=6000,r=0.01,m;m=log10(p/(p-d*r)/log10(1+r);printf("m=%6.2fn",m);return 0;3-4#include <stdio.h>int main()int c1,c2;c1=197;c2=198;printf("c1=%c,c2=%cn",c1,c2);printf("c1=%d，c2=%dn",c1,c2);return 0;3-5#include <stdio.h>int main()int a,b;float x,y;char c1,c2;scanf("a=%d b=%d",&a,&b);scanf("%f %e",&x,&y);scanf("%c%c",&c1,&c2);printf("a=%d,b=%d,x=%f,y=%f,c1=%c,c2=%cn",a,b,x,y,c1,c2);return 0;3-6#include <stdio.h>int main()char c1=C,c2=h,c3=i,c4=n,c5=a;c1=c1+4;c2=c2+4;c3=c3+4;c4=c4+4;c5=c5+4;printf("passwor is %c%c%c%c%cn",c1,c2,c3,c4,c5);return 0;3-7#include <stdio.h>int main ()float h,r,l,s,sq,vq,vz;float pi=3.141526;printf("請(qǐng)輸入圓半徑r，圓柱高h(yuǎn)");scanf("%f,%f",&r,&h); /要求輸入圓半徑r和圓柱高h(yuǎn)l=2*pi*r; /計(jì)算圓周長(zhǎng)ls=r*r*pi; /計(jì)算圓面積ssq=4*pi*r*r; /計(jì)算圓球表面積sqvq=3.0/4.0*pi*r*r*r; /計(jì)算圓球體積vqvz=pi*r*r*h; /計(jì)算圓柱體積vzprintf("圓周長(zhǎng)為: l=%6.2fn",l);printf("圓面積為: s=%6.2fn",s);printf("圓球表面積為: sq=%6.2fn",sq);printf("圓球體積為: v=%6.2fn",vq);printf("圓柱體積為: vz=%6.2fn",vz);return 0;3-8-1#include <stdio.h>int main()int c1,c2; /整型定義printf("請(qǐng)輸入兩個(gè)整數(shù)c1,c2:");scanf("%d,%d",&c1,&c2);printf("按字符輸出結(jié)果:n");printf("%c,%cn",c1,c2);printf("按ASCII碼輸出結(jié)果為:n");printf("%d,%dn",c1,c2);return 0;3-8-2#include <stdio.h>int main()char c1,c2; /定義字符型變量int i1,i2; /定義整型變量printf("請(qǐng)輸入兩個(gè)字符c1,c2:");scanf("%c,%c",&c1,&c2);i1=c1; /賦值給整型變量i2=c2;printf("按字符輸出結(jié)果:n");printf("%c,%cn",i1,i2);printf("按整數(shù)輸出結(jié)果:n");printf("%d,%dn",c1,c2);return 0;3-8-3#include <stdio.h>int main()char c1,c2; /定義為字符型int i1,i2; /定義為整型printf("請(qǐng)輸入兩個(gè)整數(shù)i1,i2:");scanf("%d,%d",&i1,&i2);c1=i1; /將整數(shù)賦值給字符變量c2=i2;printf("按字符輸出結(jié)果:n");printf("%c,%cn",c1,c2);printf("按整數(shù)輸出結(jié)果:n");printf("%d,%dn",c1,c2);return 0;3-8#include <stdio.h>int main()char c1,c2;printf("請(qǐng)輸入兩個(gè)字符c1,c2:");c1=getchar();c2=getchar();printf("用putchar語(yǔ)句輸出結(jié)果為:");putchar(c1);putchar(c2);printf("n");printf("用printf語(yǔ)句輸出結(jié)果為:");printf("%c %cn",c1,c2);return 0;第4章選擇結(jié)構(gòu)程序設(shè)計(jì)854.1選擇結(jié)構(gòu)和條件判斷854.2用if語(yǔ)句實(shí)現(xiàn)選擇結(jié)構(gòu)874.2.1用if語(yǔ)句處理選擇結(jié)構(gòu)舉例874.2.2if語(yǔ)句的一般形式 894.3關(guān)系運(yùn)算符和關(guān)系表達(dá)式914.3.1關(guān)系運(yùn)算符及其優(yōu)先次序914.3.2關(guān)系表達(dá)式924.4邏輯運(yùn)算符和邏輯表達(dá)式924.4.1邏輯運(yùn)算符及其優(yōu)先次序934.4.2邏輯表達(dá)式944.4.3邏輯型變量964.5條件運(yùn)算符和條件表達(dá)式974.6選擇結(jié)構(gòu)的嵌套994.7用switch語(yǔ)句實(shí)現(xiàn)多分支選擇結(jié)構(gòu)1024.8選擇結(jié)構(gòu)程序綜合舉例105習(xí)題1114-4-1#include <stdio.h>int main()int a,b,c;printf("請(qǐng)輸入三個(gè)整數(shù):");scanf("%d,%d,%d",&a,&b,&c);if (a<b)if (b<c)printf("max=%dn",c);elseprintf("max=%dn",b);else if (a<c)printf("max=%dn",c);elseprintf("max=%dn",a);return 0;4-4-2#include <stdio.h>int main() int a,b,c,temp,max;printf("請(qǐng)輸入三個(gè)整數(shù):");scanf("%d,%d,%d",&a,&b,&c);temp=(a>b)?a:b; /*將a和b中的大者存入temp中*/max=(temp>c)?temp:c; /*將a和b中的大者與c比較,取最大者*/ printf("三個(gè)整數(shù)的最大數(shù)是%dn",max);return 0;4-5-2#include <stdio.h>#include <math.h>#define M 1000int main()int i,k;printf("請(qǐng)輸入一個(gè)小于%d的整數(shù)i:",M);scanf("%d",&i);while (i>M)printf("輸入的數(shù)不符合要求，請(qǐng)重新輸入一個(gè)小于%d的整數(shù)i:",M);scanf("%d",&i);k=sqrt(i);printf("%d的平方根的整數(shù)部分是：%dn",i,k);return 0;4-5#include <stdio.h>#include <math.h>#define M 1000int main()int i,k;printf("請(qǐng)輸入一個(gè)小于%d的整數(shù)i:",M);scanf("%d",&i);if (i>M)printf("輸入的數(shù)不符合要求，請(qǐng)重新輸入一個(gè)小于%d的整數(shù)i:",M);scanf("%d",&i);k=sqrt(i);printf("%d的平方根的整數(shù)部分是：%dn",i,k);return 0;4-6.#include <stdio.h>int main() int x,y;printf("輸入x:");scanf("%d",&x);if(x<1) /* x<1 */ y=x;printf("x=%3d, y=x=%dn" ,x,y);else if(x<10) /* 1=<x<10 */ y=2*x-1;printf("x=%d, y=2*x-1=%dn",x,y);else /* x>=10 */ y=3*x-11;printf("x=%d, y=3*x-11=%dn",x,y);return 0;4-7-1#include <stdio.h>int main()int x,y;printf("enter x:");scanf("%d",&x);y=-1;if(x!=0)if(x>0)y=1;elsey=0;printf("x=%d,y=%dn",x,y);return 0;4-7-2#include <stdio.h>int main()int x,y;printf("please enter x:");scanf("%d",&x);y=0;if(x>=0)if(x>0) y=1;else y=-1;printf("x=%d,y=%dn",x,y);return 0;4-8#include <stdio.h>int main() float score;char grade;printf("請(qǐng)輸入學(xué)生成績(jī):");scanf("%f",&score);while (score>100|score<0)printf("n 輸入有誤,請(qǐng)重輸");scanf("%f",&score);switch(int)(score/10)case 10:case 9: grade=A;break;case 8: grade=B;break;case 7: grade=C;break;case 6: grade=D;break;case 5:case 4:case 3:case 2:case 1:case 0: grade=E;printf("成績(jī)是 %5.1f,相應(yīng)的等級(jí)是%cn ",score,grade);return 0;4-9#include <stdio.h>#include <math.h>int main()int num,indiv,ten,hundred,thousand,ten_thousand,place;位,萬(wàn)位和位數(shù)printf("請(qǐng)輸入一個(gè)整數(shù)(0-99999):");scanf("%d",&num);if (num>9999)place=5;else if (num>999)place=4;else if (num>99) /分別代表個(gè)位,十位,百位,千place=3;else if (num>9)place=2;else place=1;printf("位數(shù):%dn",place);printf("每位數(shù)字為:");ten_thousand=num/10000;thousand=(int)(num-ten_thousand*10000)/1000;hundred=(int)(num-ten_thousand*10000-thousand*1000)/100;ten=(int)(num-ten_thousand*10000-thousand*1000-hundred*100)/10;indiv=(int)(num-ten_thousand*10000-thousand*1000-hundred*100-ten*10);switch(place)case 5:printf("%d,%d,%d,%d,%d",ten_thousand,thousand,hundred,ten,indiv);printf("n反序數(shù)字為:");printf("%d%d%d%d%dn",indiv,ten,hundred,thousand,ten_thousand);break;case 4:printf("%d,%d,%d,%d",thousand,hundred,ten,indiv);printf("n反序數(shù)字為:");printf("%d%d%d%dn",indiv,ten,hundred,thousand);break;case 3:printf("%d,%d,%d",hundred,ten,indiv);printf("n反序數(shù)字為:");printf("%d%d%dn",indiv,ten,hundred);break;case 2:printf("%d,%d",ten,indiv);printf("n反序數(shù)字為:");printf("%d%dn",indiv,ten);break;case 1:printf("%d",indiv);printf("n反序數(shù)字為:");printf("%dn",indiv);break;return 0;4-10-1#include <stdio.h>int main()int i;double bonus,bon1,bon2,bon4,bon6,bon10;bon1=100000*0.1;bon2=bon1+100000*0.075;bon4=bon2+100000*0.05;bon6=bon4+100000*0.03;bon10=bon6+400000*0.015;printf("請(qǐng)輸入利潤(rùn)i:");scanf("%d",&i);if (i<=100000)bonus=i*0.1;else if (i<=200000)bonus=bon1+(i-100000)*0.075;else if (i<=400000)bonus=bon2+(i-200000)*0.05;else if (i<=600000)bonus=bon4+(i-400000)*0.03;else if (i<=1000000)bonus=bon6+(i-600000)*0.015;elsebonus=bon10+(i-1000000)*0.01;printf("獎(jiǎng)金是: %10.2fn",bonus);return 0;4-10-2#include <stdio.h>int main()int i;double bonus,bon1,bon2,bon4,bon6,bon10;int branch;bon1=100000*0.1;bon2=bon1+100000*0.075;bon4=bon2+200000*0.05;bon6=bon4+200000*0.03;bon10=bon6+400000*0.015;printf("請(qǐng)輸入利潤(rùn)i:");scanf("%d",&i);branch=i/100000;if (branch>10) branch=10;switch(branch) case 0:bonus=i*0.1;break;case 1:bonus=bon1+(i-100000)*0.075;break;case 2:case 3: bonus=bon2+(i-200000)*0.05;break;case 4:case 5: bonus=bon4+(i-400000)*0.03;break;case 6:case 7:case 8:case 9: bonus=bon6+(i-600000)*0.015;break;case 10: bonus=bon10+(i-1000000)*0.01;printf("獎(jiǎng)金是 %10.2fn",bonus);return 0;4-11#include <stdio.h>int main()int t,a,b,c,d;printf("請(qǐng)輸入四個(gè)數(shù):");scanf("%d,%d,%d,%d",&a,&b,&c,&d);printf("a=%d,b=%d,c=%d,d=%dn",a,b,c,d);if (a>b) t=a;a=b;b=t;if (a>c) t=a;a=c;c=t;if (a>d) t=a;a=d;d=t;if (b>c) t=b;b=c;c=t;if (b>d) t=b;b=d;d=t;if (c>d) t=c;c=d;d=t;printf("排序結(jié)果如下: n");printf("%d %d %d %d n" ,a,b,c,d);return 0;4-12#include <stdio.h>int main()int h=10;float x1=2,y1=2,x2=-2,y2=2,x3=-2,y3=-2,x4=2,y4=-2,x,y,d1,d2,d3,d4;printf("請(qǐng)輸入一個(gè)點(diǎn)(x,y):");scanf("%f,%f",&x,&y);d1=(x-x4)*(x-x4)+(y-y4)*(y-y4); /*求該點(diǎn)到各中心點(diǎn)距離*/d2=(x-x1)*(x-x1)+(y-y1)*(y-y1);d3=(x-x2)*(x-x2)+(y-y2)*(y-y2);d4=(x-x3)*(x-x3)+(y-y3)*(y-y3);if (d1>1 && d2>1 && d3>1 && d4>1) h=0; /*判斷該點(diǎn)是否在塔外*/printf("該點(diǎn)高度為 %dn",h);return 0;第5章循環(huán)結(jié)構(gòu)程序設(shè)計(jì)1145.1為什么需要循環(huán)控制1145.2用while語(yǔ)句實(shí)現(xiàn)循環(huán)1155.3用dowhile語(yǔ)句實(shí)現(xiàn)循環(huán)1175.4用for 語(yǔ)句實(shí)現(xiàn)循環(huán)1205.5循環(huán)的嵌套1245.6幾種循環(huán)的比較1255.7改變循環(huán)執(zhí)行的狀態(tài)1255.7.1用break語(yǔ)句提前終止循環(huán)1265.7.2用continue語(yǔ)句提前結(jié)束本次循環(huán)1275.7.3break語(yǔ)句和continue語(yǔ)句的區(qū)別1285.8循環(huán)程序舉例131習(xí)題1405-2#include <stdio.h>#include <math.h> / 程序中用到數(shù)學(xué)函數(shù)fabs，應(yīng)包含頭文件math.n int main()int sign=1,count=0; / sign用來(lái)表示數(shù)值的符號(hào),count用來(lái)統(tǒng)計(jì)循環(huán)次數(shù) double pi=0.0,n=1.0,term=1.0; / pi開(kāi)始代表多項(xiàng)式的值，最后代表的值, n代表分母，term代表當(dāng)前項(xiàng)的值while(fabs(term)>=1e-8) / 檢查當(dāng)前項(xiàng)term的絕對(duì)值是否大于或等于10的(-6)次方pi=pi+term; / 把當(dāng)前項(xiàng)term累加到pi中n=n+2; / n+2是下一項(xiàng)的分母sign=-sign; / sign代表符號(hào)，下一項(xiàng)的符號(hào)與上一項(xiàng)符號(hào)相反 term=sign/n; / 求出下一項(xiàng)的值termcount+; / count累加1pi=pi*4; / 多項(xiàng)式的和pi乘以4，才是的近似值 printf("pi=%10.8fn",pi); / 輸出的近似值printf("count=%dn",count); / 輸出循環(huán)次數(shù)return 0;5-3#include <stdio.h>int main()int p,r,n,m,temp;printf("請(qǐng)輸入兩個(gè)正整數(shù)n,m:");scanf("%d,%d,",&n,&m);if (n<m)temp=n;n=m;m=temp;p=n*m;while(m!=0)r=n%m;n=m;m=r;printf("它們的最大公約數(shù)為:%dn",n);printf("它們的最小公約數(shù)為:%dn",p/n);return 0;5-4#include <stdio.h>int main()char c;int letters=0,space=0,digit=0,other=0;printf("請(qǐng)輸入一行字符:n");while(c=getchar()!=n)if (c>=a && c<=z | c>=A && c<=Z)letters+;else if (c= )space+;else if (c>=0 && c<=9)digit+;elseother+;printf("字母數(shù):%dn空格數(shù):%dn數(shù)字?jǐn)?shù):%dn其它字符數(shù):%dn",letters,space,digit,other); return 0;5-5#include <stdio.h>int main()int a,n,i=1,sn=0,tn=0;printf("a,n=:");scanf("%d,%d",&a,&n);while (i<=n)tn=tn+a; /*賦值后的tn為i個(gè) a組成數(shù)的值*/sn=sn+tn; /*賦值后的sn為多項(xiàng)式前i項(xiàng)之和*/a=a*10;+i;printf("a+aa+aaa+.=%dn",sn);return 0;5-6#include <stdio.h>int main()double s=0,t=1;int n;for (n=1;n<=20;n+)t=t*n;s=s+t;printf("1!+2!+.+20!=%22.15en",s);return 0;5-7#include <stdio.h>int main()int n1=100,n2=50,n3=10;double k,s1=0,s2=0,s3=0;for (k=1;k<=n1;k+) /*計(jì)算1到100的和*/s1=s1+k;for (k=1;k<=n2;k+) /*計(jì)算1到50各數(shù)的平方和*/s2=s2+k*k;for (k=1;k<=n3;k+) /*計(jì)算1到10的各倒數(shù)和*/s3=s3+1/k;printf("sum=%15.6fn",s1+s2+s3);return 0;5-8#include <stdio.h>int main()int i,j,k,n;printf("parcissus numbers are ");for (n=100;n<1000;n+)i=n/100;j=n/10-i*10;k=n%10;if (n=i*i*i + j*j*j + k*k*k)printf("%d ",n);printf("n");return 0;5-9-1#define M 1000 /*定義尋找范圍*/#include <stdio.h>int main()int k1,k2,k3,k4,k5,k6,k7,k8,k9,k10;int i,a,n,s;for (a=2;a<=M;a+) /* a是2-1000之間的整數(shù)，檢查它是否完數(shù) */n=0; /* n用來(lái)累計(jì)a的因子的個(gè)數(shù) */s=a; /* s用來(lái)存放尚未求出的因子之和，開(kāi)始時(shí)等于a */ for (i=1;i<a;i+) /* 檢查i是否a的因子 */if (a%i=0) /* 如果i是a的因子 */n+; /* n加1，表示新找到一個(gè)因子 */s=s-i; /* s減去已找到的因子，s的新值是尚未求出的因子之和 */ switch(n) /* 將找到的因子賦給k1.k9，或k10 */case 1:k1=i; break; /* 找出的笫1個(gè)因子賦給k1 */case 2:k2=i; break; /* 找出的笫2個(gè)因子賦給k2 */case 3:k3=i; break; /* 找出的笫3個(gè)因子賦給k3 */case 4:k4=i; break; /* 找出的笫4個(gè)因子賦給k4 */case 5:k5=i; break; /* 找出的笫5個(gè)因子賦給k5 */case 6:k6=i; break; /* 找出的笫6個(gè)因子賦給k6 */case 7:k7=i; break; /* 找出的笫7個(gè)因子賦給k7 */case 8:k8=i; break; /* 找出的笫8個(gè)因子賦給k8 */case 9:k9=i; break; /*找出的笫9個(gè)因子賦給k9 */case 10:k10=i; break; /* 找出的笫10個(gè)因子賦給k10 */if (s=0)printf("%d ,Its factors are ",a);if (n>1) printf("%d,%d",k1,k2); /* n>1表示a至少有2個(gè)因子 */if (n>2) printf(",%d",k3); /* n>2表示至少有3個(gè)因子，故應(yīng)再輸出一個(gè)因子 */if (n>3) printf(",%d",k4); /* n>3表示至少有4個(gè)因子，故應(yīng)再輸出一個(gè)因子 */if (n>4) printf(",%d",k5); /* 以下類(lèi)似 */if (n>5) printf(",%d",k6);if (n>6) printf(",%d",k7);if (n>7) printf(",%d",k8);if (n>8) printf(",%d",k9);if (n>9) printf(",%d",k10);printf("n");return 0;5-9-2#include <stdio.h>int main()int m,s,i;for (m=2;m<1000;m+)s=0;for (i=1;i<m;i+)if (m%i)=0) s=s+i;if(s=m)printf("%d,its factors are ",m);for (i=1;i<m;i+)if (m%i=0) printf("%d ",i);printf("n");return 0;5-10#include <stdio.h>int main()int i,n=20;double a=2,b=1,s=0,t;for (i=1;i<=n;i+)s=s+a/b;t=a,a=a+b,b=t;printf("sum=%16.10fn",s);return 0;5-11#include <stdio.h>int main()double sn=100,hn=sn/2;int n;for (n=2;n<=10;n+)sn=sn+2*hn; /*第n次落地時(shí)共經(jīng)過(guò)的米數(shù)*/hn=hn/2; /*第n次反跳高度*/printf("第10次落地時(shí)共經(jīng)過(guò)%f米n",sn);printf("第10次反彈%f米n",hn);return 0;5-12#include <stdio.h>int main()int day,x1,x2;day=9;x2=1;while(day>0)x1=(x2+1)*2; /*第1天的桃子數(shù)是第2天桃子數(shù)加1后的2倍.*/x2=x1;day-;printf("total=%dn",x1);return 0;5-13#include <stdio.h>#include <math.h>int main()float a,x0,x1;printf("enter a positive number:");scanf("%f",&a);x0=a/2;x1=(x0+a/x0)/2;dox0=x1;x1=(x0+a/x0)/2;while(fabs(x0-x1)>=1e-5);printf("The square root of %5.2f is %8.5fn",a,x1);return 0;5-14#include <stdio.h>#include <math.h>int main()double x1,x0,f,f1;x1=1.5;dox0=x1;f=(2*x0-4)*x0+3)*x0-6;f1=(6*x0-8)*x0+3;x1=x0-f/f1;while(fabs(x1-x0)>=1e-5);printf("The root of equation is %5.2fn",x1);return 0;5-15#include <stdio.h>#include <math.h>int main()float x0,x1,x2,fx0,fx1,fx2;doprintf("enter x1 & x2:");scanf("%f,%f",&x1,&x2);fx1=x1*(2*x1-4)*x1+3)-6;fx2=x2*(2*x2-4)*x2+3)-6;while(fx1*fx2>0);dox0=(x1+x2)/2;fx0=x0*(2*x0-4)*x0+3)-6;if (fx0*fx1)<0)x2=x0;fx2=fx0;elsex1=x0;fx1=fx0;while(fabs (fx0)>=1e-5);printf("x=%6.2fn",x0);return 0;5-16#include <stdio.h>int main()int i,j,k;for (i=0;i<=3;i+)for (j=0;j<=2-i;j+)printf(" ");for (k=0;k<=2*i;k+)printf("*");printf("n");for (i=0;i<=2;i+)for (j=0;j<=i;j+)printf(" ");for (k=0;k<=4-2*i;k+)printf("*");printf("n");return 0;5-17#include <stdio.h>int main()char i,j,k; /*是a的對(duì)手;j是b的對(duì)手;k是c的對(duì)手*/for (i=x;i<=z;i+)for (j=x;j<=z;j+)if (i!=j)for (k=x;k<=z;k+)if (i!=k && j!=k)if (i!=x && k!=x && k!=z)printf("A-%cnB-%cnC-%cn",i,j,k);return 0;第6章利用數(shù)組處理批量數(shù)據(jù)1426.1怎樣定義和引用一維數(shù)組1426.1.1怎樣定義一維數(shù)組1436.1.2怎樣引用一維數(shù)組元素1446.1.3一維數(shù)組的初始化1456.1.4一維數(shù)組程序舉例1466.2怎樣定義和引用二維數(shù)組1486.2.1怎樣定義二維數(shù)組1496.2.2怎樣引用二維數(shù)組的元素1506.2.3二維數(shù)組的初始化1516.2.4二維數(shù)組程序舉例1526.3字符數(shù)組1546.3.1怎樣定義字符數(shù)組1546.3.2字符數(shù)組的初始化1556.3.3怎樣引用字符數(shù)組中的元素1556.3.4字符串和字符串結(jié)束標(biāo)志1566.3.5字符數(shù)組的輸入輸出1596.3.6使用字符串處理函數(shù)1616.3.7字符數(shù)組應(yīng)用舉例165習(xí)題1686-1#include <stdio.h>#include <math.h>int main()int i,j,n,a101;for (i=1;i<=100;i+)ai=i;a1=0;for (i=2;i<sqrt(100);i+)for (j=i+1;j<=100;j+)if(ai!=0 && aj!=0)if (aj%ai=0)aj=0;printf("n");for (i=2,n=0;i<=100;i+) if(ai!=0)printf("%5d",ai);n+;if(n=10)printf("n");n=0;printf("n");return 0;6-2#include <stdio.h>int main()int i,j,min,temp,a11;printf("enter data:n");for (i=1;i<=10;i+)printf("a%d=",i);scanf("%d",&ai);printf("n");printf("The orginal numbers:n");for (i=1;i<=10;i+)printf("%5d",ai);printf("n");for (i=1;i<=9;i+)min=i;for (j=i+1;j<=10;j+)if (amin>aj) min=j;temp=ai;ai=amin;amin=temp;printf("nThe sorted numbers:n");for (i=1;i<=10;i+)printf("%5d",ai);printf("n");return 0;6-3#include <stdio.h>int main()int a33,sum=0;int i,j;printf("enter data:n");for (i=0;i<3;i+)for (j=0;j<3;j+)scanf("%3d",&aij);for (i=0;i<3;i+)sum=sum+aii;printf("sum=%6dn",sum);return 0;6-4#include <stdio.h>int main() int a11=1,4,6,9,13,16,19,28,40,100;int temp1,temp2,number,end,i,j;printf("array a:n");for (i=0;i<10;i+)printf("%5d",ai);printf("n");printf("insert data:");scanf("%d",&number);end=a9;if (number>end)a10=number;elsefor (i=0;i<10;i+)if (ai>number)temp1=ai;ai=number;for (j=i+1;j<11;j+)temp2=aj;aj=temp1;temp1=temp2;break;printf("Now array a:n");for (i=0;i<11;i+)printf("%5d",ai);printf("n");return 0;6-5#include <stdio.h>#define N 5int main() int aN,i,temp;printf("enter array a:n");for (i=0;i