2.5指數(shù)與指數(shù)函數(shù),知識(shí)梳理,考點(diǎn)自測(cè),1.根式(1)根式的概念(2)根式的性質(zhì),知識(shí)梳理,考點(diǎn)自測(cè),2.實(shí)數(shù)指數(shù)冪(1)分?jǐn)?shù)指數(shù)冪的表示0的正分?jǐn)?shù)指數(shù)冪是,0的負(fù)分?jǐn)?shù)指數(shù)冪無(wú)意義.(2)有理數(shù)指數(shù)冪的運(yùn)算性質(zhì)aras=(a>0,r,sQ).(ar)s=(a>0,r,sQ).(ab)r=(a>0,b>0,rQ).,0,ar+s,ars,arbr,知識(shí)梳理,考點(diǎn)自測(cè),(3)無(wú)理數(shù)指數(shù)冪一般地,無(wú)理數(shù)指數(shù)冪a(a>0,是無(wú)理數(shù))是一個(gè)的實(shí)數(shù),有理數(shù)指數(shù)冪的運(yùn)算性質(zhì)于無(wú)理數(shù)指數(shù)冪.,確定,同樣適用,知識(shí)梳理,考點(diǎn)自測(cè),3.指數(shù)函數(shù)的圖象和性質(zhì),上方,(0,1),知識(shí)梳理,考點(diǎn)自測(cè),R,(0,+),單調(diào)遞減,單調(diào)遞增,y=1,y>1,0<y<1,0<y1,知識(shí)梳理,考點(diǎn)自測(cè),2,3,4,1,5,答案,知識(shí)梳理,考點(diǎn)自測(cè),2,3,4,1,5,2.函數(shù)y=2|x|的值域?yàn)?)A.0,+)B.1,+)C.(1,+)D.(0,1,答案,解析,知識(shí)梳理,考點(diǎn)自測(cè),2,3,4,1,5,A.是偶函數(shù),且在R上是增函數(shù)B.是奇函數(shù),且在R上是增函數(shù)C.是偶函數(shù),且在R上是減函數(shù)D.是奇函數(shù),且在R上是減函數(shù),答案,解析,知識(shí)梳理,考點(diǎn)自測(cè),2,3,4,1,5,4.(2017廣西桂林模擬)已知x0,a1)的圖象,可將指數(shù)函數(shù)y=ax(a>0,a1)的圖象向右平移1個(gè)單位長(zhǎng)度,再向上平移4個(gè)單位長(zhǎng)度.則點(diǎn)(0,1)平移后得到點(diǎn)(1,5).故點(diǎn)P的坐標(biāo)為(1,5).,考點(diǎn)1,考點(diǎn)2,考點(diǎn)3,(3)曲線|y|=2x+1與直線y=b的圖象如圖所示.因?yàn)榍€|y|=2x+1與直線y=b沒(méi)有公共點(diǎn),所以-1b1.故b的取值范圍是-1,1.,考點(diǎn)1,考點(diǎn)2,考點(diǎn)3,思考畫(huà)指數(shù)函數(shù)的圖象及應(yīng)用指數(shù)函數(shù)的圖象解決問(wèn)題時(shí)應(yīng)注意什么?解題心得1.畫(huà)指數(shù)函數(shù)y=ax(a>0,且a1)的圖象,應(yīng)抓住三個(gè)關(guān)鍵2.與指數(shù)函數(shù)有關(guān)的函數(shù)圖象的研究,往往利用相應(yīng)指數(shù)函數(shù)的圖象,通過(guò)平移、對(duì)稱變換得到其圖象.3.一些指數(shù)方程、不等式問(wèn)題的求解,往往利用相應(yīng)的指數(shù)型函數(shù)圖象數(shù)形結(jié)合求解.,考點(diǎn)1,考點(diǎn)2,考點(diǎn)3,對(duì)點(diǎn)訓(xùn)練2(1)若函數(shù)y=2-x+1+m的圖象不經(jīng)過(guò)第一象限,則m的取值范圍是;(2)若函數(shù)f(x)=ax-1(a>0,且a1)的定義域和值域都是0,2,則實(shí)數(shù)a=.,答案,解析,考點(diǎn)1,考點(diǎn)2,考點(diǎn)3,考向1比較指數(shù)式的大小A.b<a<cB.a<b<cC.b<c<aD.c<a0時(shí),函數(shù)f(x)=(aex+b)(x-2)單調(diào)遞增,且函數(shù)y=f(x-1)的圖象關(guān)于直線x=1對(duì)稱,則使得f(2-m)>0成立的m的取值范圍是()A.m|m2B.m|-24D.m|0<m1時(shí),af(x)ag(x)恒成立f(x)g(x)恒成立f(x)-g(x)0恒成立f(x)-g(x)min0.(2)當(dāng)0<a1及0<a<1進(jìn)行分類討論.,